Integrand size = 25, antiderivative size = 120 \[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=\frac {10 e^4 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{21 a^4 d \sqrt {e \cos (c+d x)}}-\frac {4 e (e \cos (c+d x))^{5/2}}{7 a d (a+a \sin (c+d x))^3}+\frac {20 e^3 \sqrt {e \cos (c+d x)}}{21 d \left (a^4+a^4 \sin (c+d x)\right )} \]
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Time = 0.10 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {2759, 2721, 2720} \[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=\frac {10 e^4 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{21 a^4 d \sqrt {e \cos (c+d x)}}+\frac {20 e^3 \sqrt {e \cos (c+d x)}}{21 d \left (a^4 \sin (c+d x)+a^4\right )}-\frac {4 e (e \cos (c+d x))^{5/2}}{7 a d (a \sin (c+d x)+a)^3} \]
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Rule 2720
Rule 2721
Rule 2759
Rubi steps \begin{align*} \text {integral}& = -\frac {4 e (e \cos (c+d x))^{5/2}}{7 a d (a+a \sin (c+d x))^3}-\frac {\left (5 e^2\right ) \int \frac {(e \cos (c+d x))^{3/2}}{(a+a \sin (c+d x))^2} \, dx}{7 a^2} \\ & = -\frac {4 e (e \cos (c+d x))^{5/2}}{7 a d (a+a \sin (c+d x))^3}+\frac {20 e^3 \sqrt {e \cos (c+d x)}}{21 d \left (a^4+a^4 \sin (c+d x)\right )}+\frac {\left (5 e^4\right ) \int \frac {1}{\sqrt {e \cos (c+d x)}} \, dx}{21 a^4} \\ & = -\frac {4 e (e \cos (c+d x))^{5/2}}{7 a d (a+a \sin (c+d x))^3}+\frac {20 e^3 \sqrt {e \cos (c+d x)}}{21 d \left (a^4+a^4 \sin (c+d x)\right )}+\frac {\left (5 e^4 \sqrt {\cos (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{21 a^4 \sqrt {e \cos (c+d x)}} \\ & = \frac {10 e^4 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right )}{21 a^4 d \sqrt {e \cos (c+d x)}}-\frac {4 e (e \cos (c+d x))^{5/2}}{7 a d (a+a \sin (c+d x))^3}+\frac {20 e^3 \sqrt {e \cos (c+d x)}}{21 d \left (a^4+a^4 \sin (c+d x)\right )} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.05 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.55 \[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=-\frac {(e \cos (c+d x))^{9/2} \operatorname {Hypergeometric2F1}\left (\frac {9}{4},\frac {11}{4},\frac {13}{4},\frac {1}{2} (1-\sin (c+d x))\right )}{9\ 2^{3/4} a^4 d e (1+\sin (c+d x))^{9/4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(400\) vs. \(2(132)=264\).
Time = 6.54 (sec) , antiderivative size = 401, normalized size of antiderivative = 3.34
\[\frac {2 \left (-40 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+128 \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+60 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-128 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )-30 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-112 \left (\sin ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-16 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+5 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, F\left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+112 \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-4 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e^{4}}{21 \left (8 \left (\sin ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-12 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+6 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1\right ) a^{4} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, d}\]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.11 (sec) , antiderivative size = 188, normalized size of antiderivative = 1.57 \[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=\frac {5 \, {\left (-i \, \sqrt {2} e^{3} \cos \left (d x + c\right )^{2} + 2 i \, \sqrt {2} e^{3} \sin \left (d x + c\right ) + 2 i \, \sqrt {2} e^{3}\right )} \sqrt {e} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + 5 \, {\left (i \, \sqrt {2} e^{3} \cos \left (d x + c\right )^{2} - 2 i \, \sqrt {2} e^{3} \sin \left (d x + c\right ) - 2 i \, \sqrt {2} e^{3}\right )} \sqrt {e} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) - 8 \, {\left (4 \, e^{3} \sin \left (d x + c\right ) + e^{3}\right )} \sqrt {e \cos \left (d x + c\right )}}{21 \, {\left (a^{4} d \cos \left (d x + c\right )^{2} - 2 \, a^{4} d \sin \left (d x + c\right ) - 2 \, a^{4} d\right )}} \]
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Timed out. \[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=\text {Timed out} \]
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\[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=\int { \frac {\left (e \cos \left (d x + c\right )\right )^{\frac {7}{2}}}{{\left (a \sin \left (d x + c\right ) + a\right )}^{4}} \,d x } \]
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\[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=\int { \frac {\left (e \cos \left (d x + c\right )\right )^{\frac {7}{2}}}{{\left (a \sin \left (d x + c\right ) + a\right )}^{4}} \,d x } \]
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Timed out. \[ \int \frac {(e \cos (c+d x))^{7/2}}{(a+a \sin (c+d x))^4} \, dx=\int \frac {{\left (e\,\cos \left (c+d\,x\right )\right )}^{7/2}}{{\left (a+a\,\sin \left (c+d\,x\right )\right )}^4} \,d x \]
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